Chapter 3
Required:
I. Complete the following 7 problems:
- Exercise 3-8, p. 94
- Exercise 3-15, p. 99
- Exercise 3-27, p. 109
- For (a), use both the direct definition of the expected value of \(X\) and the survival function trick. See II. below for the survival function trick.
- Exercise 3-29, p. 110
- Sample Exam Problem 3-2, p. 128
- Sample Exam Problem 3-5, p. 129
- Sample Exam Problem 3-14, p. 131
II. Prove the survival function trick for discrete random variables:
Theorem: Let \(N\) be a nonnegative discrete random variable with finite mean. Then
\[ E[N] = \sum_{n = 0}^{\infty} P(N > n).\]
Hints:
- This theorem is easiest to prove by starting from the right-hand side.
- Start by expanding \(P(N > n)\) in terms of the probability mass function of \(N\).
- It will be useful to write each expanded term on a single line, and align the different lines based on the probability mass function terms in a term's expansion.
III. Prove the following property for a discrete random variable \(X\) with finite mean.
Theorem: Let \(X\) be a random variable with mean \(E[X]\), and let \(a, b\) be real (non-random) constants. Then
\[E[a X + b] = a E[X] + b.\]
Hint:
- Use the result for the expectation of a function \(g\) of a random variable \(X\), and take advantage of properties of sums and probability mass functions.
IV. Complete two problems from Problem Solving Session 1 that you did not solve during the problem solving session and that were not presented by the student presenters.